1=2
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That there is no such thing as zero volume
Yes there is. If something does not exist inside of space-such as the singularity-then it has no volume since space is needed for volume since volume is based off of space.
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Yes there is. If something does not exist inside of space-such as the singularity-then it has no volume since space is needed for volume since volume is based off of space.
If it does not exist, then it is not there so how can you measure anything, even volume??????????
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If it does not exist, then it is not there so how can you measure anything, even volume??????????
I know what you're trying to say.
Volume describes three-dimensional space, since v= length X width X height.
If there is no space, then there can be no volume, hence the volume is zero since it does not exist.
peace peace peace
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I know what you're trying to say.
Volume describes three-dimensional space, since v= length X width X height.
If there is no space, then there can be no volume, hence the volume is zero since it does not exist.
peace peace peace
If it does not exist then nor does the zero
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If it does not exist then nor does the zero
confused
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I know what you're trying to say.
Volume describes three-dimensional space, since v= length X width X height.
If there is no space, then there can be no volume, hence the volume is zero since it does not exist.
peace peace peace
The volume is zero when the volume is zero and space exists,
when space does not exist, volume does not exist as a concept, leave alone with a determinable volume.
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On a similar note, I submit the following proofs for your pleasure
The square root of -1 is i.
1 = sqrt (i^2 * i^2)
1 = sqrt (i^4)
1 = i^2
1 = -1or
i squared = -1
take square root of both sides
sqrt i squared = sqrt -1
divide each side by 1
i / 1 = (sqrt -1) / 1
take the reciprocal of each side
1 / i = 1 / sqrt -1
oops, a negative in the denominator...fix it!
1 / i = -1 / sqrt 1
multiply both sides by i
i * 1/i = i * -1 / sqrt 1
simplify
i / i = -i / 1
simplify
1 = -i
solve for i
-1 = i
solve for i square; square both sides
-1^2 = i^2
simplify
1 = i squaredHOWEVER, by definition -1 equals i squared
THEREFORE, it follows that -1 = 1 -
Does 0 equal 0 (0=0)?
Yes
Does 0 x 1 equal 0 (0 x 1=0)?
Yes
Does 0 x 2 equal 0 (0 x 2=0)?
Yes
Well, since 0 equals 0, and 1 x 0 equals 0, and 2 x 0 equals 0, then 0 x 1 must equal 0 x 2 (0 x 1=0 x 2).
Let's look at that more closely...
0 x 1= 0 x 2
We have to simplify this, and the only way we can do that is divide each side by zero0 x 1= 0 x 2
0 0
You can never divide by zero and the only solution to 1x = 2x is when x = 0. By dividing by x you'll only be removing the solution which is why the result becomes wrong. You can divide by x but that is only if you know that x is not zero hence http//i.imgur.com/2mIxzwM.gif sadly in this case x = 0 therefor you can't divide by x. This is why you should break out x instead or just move over the first term to the other side
x.
1 * x = 2 * x
What do you think x will be in order for them both to be equal? Zero of course.
Can even be solved like this
2 * x - 1 * x = 0
x = 0
The zeroes cancel out and you're left with one equals two (1=2). Some of you will probably say you can't divide by zero because you'e calculator won't let you, but yes you can; it equals infinity. However, in this problem it doesn't matter what it equals because the zeroes cancel out. Obviously, 1 does not equal 2, so then what does this equation and answer mean? I believe it is true when applied to infinity. Think of the question which is closer to infinity, 1 or 2? Well neither is closer than the other hence they are equally close and so 1 has the same value as 2.
My calculator says that the value is not defined which is what it's suppose to say. The reason it equals infinity for you is because your calculator is NOT dividing it by zero but rather to a number that is close to zero as possible. So in conclusion the denominator is never zero and 0/0 does NOT equal infinity but is rather considered undefined because the denominator is zero. Neither does 2/0 equal infinity either but the denominator being as close to zero as possible will equal infinity. Although this does not apply to were the numerator is zero because then the result will be zero. So 0/(0,1)^ = 0
Take the number 2 for example.
The calculator will try to come as close to zero as possible so
2/(0,1)^ and will try to put infinite amount of zeros in order to come as close to zero as possible(Note that it's approaching zero from the right side). This will give an infinite number of course. Can also be writen like this which is why your calculator sees
http//i.imgur.com/JAFCDe1.gif
The denominator i.e x can never be zero so it will try to come as close to zero as possible instead. This is why you get infinity. The smaller the denominator is the bigger the value becomes and given the fact the denominator is going to come as close to zero as possible(meaning that the denominator will only be smaller and smaller) the result will be infinite.
http//i.imgur.com/F9rfZGp.gif
The result can also be minus infinity if it is approacing the zero from the left side i.e the denominator will be smaller and smaller except that the denominator is a minus value
http//i.imgur.com/wW0qAd7.gif